Many important questions are formed in competitive exams like CUET, JEE, NEET, and boards from Class 12 Physics Unit 2. Below, we have provided Important Questions from Class 12 Physics Unit 2 Current Electricity for your JEE Mains 2023 preparation. You can check it here for revision purposes.
Latest:Â Electrostatics Class 12 JEE Questions and Answers
Electrostatics Class 12 JEE Mains Questions and Answers
We’ve compiled a list of important questions about the Current electricity physics class 12 unit 2 that you should not miss while studying for your JEE Main Exams.
Q.1. In the circuit shown, find the ratio of the power developed across 2 Ω, 4 Ω, and 6 Ω.
(a) 4 : 2 : 27
(b) 3 : 2 : 27
(c) 2 : 3 : 19
(d) 4 : 2 : 19
A.1. (a)
Explanation:
Q.2. Find the current flowing through the 6 Ω resistor in the given circuit.
(a) 5/11 A
(b) 20/11 A
(c) 8/9 A
(d) 3/7 A
A.2. (b)
Explanation:
Q.3. The total current supplied to the circuit by the battery is
(a) 1 A
(b) 2 A
(c) 4 A
(d) 6 A
A.3. (c)
Explanation:
Q.4. Current flows through a constricted conductor, as shown in the figure. The diameter D1 = 2.0 mm and the current density to the left of the constriction is j = 1.27 × 106 A m–2. (i) What current flows into the constriction? (ii) If the current density is doubled as it emerges from the right side of the constriction, what is diameter D2?
(a) 2.3 A, 1.1 mm
(b) 1.5 A, 2 mm
(c) 4.0 A, 1.4 mm
(d) 1.7 A, 2.3 mm
A.4. (c)
Explanation:
Q.5. Find the equivalent resistance between A and B.
(a) 5 Ω
(b) 7 Ω
(c) 10 Ω
(d) 9 Ω
A.5. (b)
Q.6. Consider the four circuits shown in the figure below. In which circuit power dissipated is greatest? (Neglect the internal resistance of the power supply)
A.6. (a)
Explanation:
Q.7. Two wires A and B of equal mass and of the same metal are taken. The diameter of wire A is half the diameter of wire B. If the resistance of wire A is 24 Ω, calculate the resistance of wire B.
(a) 2 Ω (b) 1.5 Ω (c) 2.5 Ω (d) 4 Ω
A.7. (b)
Explanation:
Q.8. A current of 30 A is flowing through a wire of cross-sectional area 2 mm2. Assuming the temperature of the wire to be 27°C, calculate the ratio of rms velocity to the drift velocity at this temperature. Given that Boltzmann’s constant = 1.38 × 10–23 J K–1,the density of copper = 8.9 g cm–3, atomic mass of copper = 63.
(a) 105 (b) 106 (c) 107 (d) 108
A.8. (d)
Q.9. A voltmeter of resistance 998 Ω is connected across a cell of emf 2 V and internal resistance 2 Ω. Find the potential difference across the voltmeter.
(a) 2.004 V (b) 1.996 V(c) 1.978 V (d) 1.992 V
A.9. (b)
Explanation:
Q.10. The length of a given cylindrical wire is increased by 100%. Due to the consequent decrease in diameter the change in the resistance of the wire will be
(a) 200 % (b) 100 % (c) 50 % (d) 300 %
A.10. (d)
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